extremum problem - translation to ρωσικά
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extremum problem - translation to ρωσικά

CONSTRUCT CIRCLES THAT ARE TANGENT TO THREE GIVEN CIRCLES IN A PLANE
Apollonius' problem; Problem of apollonius; Apollonius problem; Appolonius' problem; Apollonius's problem; Four coins problem
  • Figure 13: A symmetrical Apollonian gasket, also called the Leibniz packing, after its inventor [[Gottfried Leibniz]].
  • Figure 2: Four complementary pairs of solutions to Apollonius's problem; the given circles are black.
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  • ''r''<sub>''outer''</sub> + ''r''<sub>''inner''</sub>}} of the inner and outer radii, while twice its center distance ''d''<sub>''s''</sub> equals their difference.
  • ''r''<sub>''outer''</sub> − ''r''<sub>''inner''</sub>}} of the inner and outer radii, while twice its center distance ''d''<sub>''s''</sub> equals their sum.
  • The set of points with a constant ratio of distances ''d''<sub>1</sub>/''d''<sub>2</sub> to two fixed points is a circle.
  • ''r''<sub>2</sub> + ''r''<sub>''s''</sub>}}, respectively, so their difference is independent of ''r''<sub>''s''</sub>.
  • Figure 11: An Apollonius problem with no solutions. A solution circle (pink) must cross the dashed given circle (black) to touch both of the other given circles (also black).
  • radical center]] (orange).
  • Figure 9: The two tangent lines of the two tangent points of a given circle intersect on the [[radical axis]] ''R'' (red line) of the two solution circles (pink). The three points of intersection on ''R'' are the poles of the lines connecting the blue tangent points in each given circle (black).
  • Figure 6: A conjugate pair of solutions to Apollonius's problem (pink circles), with given circles in black.
  • Figure 1: A solution (in purple) to Apollonius's problem. The given circles are shown in black.
  • Figure 4: Tangency between circles is preserved if their radii are changed by equal amounts. A pink solution circle must shrink or swell with an internally tangent circle (black circle on the right), while externally tangent circles (two black circles on left) do the opposite.
  • Figure 12: The two solutions (red) to Apollonius' problem with mutually tangent given circles (black), labeled by their curvatures.
  • Figure 5: Inversion in a circle. The point ''P''<nowiki>'</nowiki> is the inverse of point ''P'' with respect to the circle.

extremum problem      

общая лексика

экстремальная задача

knapsack problem         
  • multiple constrained problem]] could consider both the weight and volume of the boxes. <br />(Solution: if any number of each box is available, then three yellow boxes and three grey boxes; if only the shown boxes are available, then all except for the green box.)
  • A demonstration of the dynamic programming approach.
PROBLEM IN COMBINATORIAL OPTIMIZATION
0/1 knapsack problem; 0-1 knapsack problem; Unbounded knapsack problem; Unbounded Knapsack Problem; Binary knapsack problem; Napsack problem; Backpack problem; 0-1 Knapsack problem; Integer knapsack problem; Knapsack Problem; Algorithms for solving knapsack problems; Methods for solving knapsack problems; Approximation algorithms for the knapsack problem; Bounded knapsack problem; Multiple knapsack problem; Rucksack problem; Computational complexity of the knapsack problem

математика

задача о ранце

knapsack problem         
  • multiple constrained problem]] could consider both the weight and volume of the boxes. <br />(Solution: if any number of each box is available, then three yellow boxes and three grey boxes; if only the shown boxes are available, then all except for the green box.)
  • A demonstration of the dynamic programming approach.
PROBLEM IN COMBINATORIAL OPTIMIZATION
0/1 knapsack problem; 0-1 knapsack problem; Unbounded knapsack problem; Unbounded Knapsack Problem; Binary knapsack problem; Napsack problem; Backpack problem; 0-1 Knapsack problem; Integer knapsack problem; Knapsack Problem; Algorithms for solving knapsack problems; Methods for solving knapsack problems; Approximation algorithms for the knapsack problem; Bounded knapsack problem; Multiple knapsack problem; Rucksack problem; Computational complexity of the knapsack problem
задача об укладке ранца (рюкзака)

Ορισμός

0/1 knapsack problem
<application> The knapsack problem restricted so that the number of each item is zero or one. (1995-03-13)

Βικιπαίδεια

Problem of Apollonius

In Euclidean plane geometry, Apollonius's problem is to construct circles that are tangent to three given circles in a plane (Figure 1). Apollonius of Perga (c. 262 BC – c. 190 BC) posed and solved this famous problem in his work Ἐπαφαί (Epaphaí, "Tangencies"); this work has been lost, but a 4th-century AD report of his results by Pappus of Alexandria has survived. Three given circles generically have eight different circles that are tangent to them (Figure 2), a pair of solutions for each way to divide the three given circles in two subsets (there are 4 ways to divide a set of cardinality 3 in 2 parts).

In the 16th century, Adriaan van Roomen solved the problem using intersecting hyperbolas, but this solution does not use only straightedge and compass constructions. François Viète found such a solution by exploiting limiting cases: any of the three given circles can be shrunk to zero radius (a point) or expanded to infinite radius (a line). Viète's approach, which uses simpler limiting cases to solve more complicated ones, is considered a plausible reconstruction of Apollonius' method. The method of van Roomen was simplified by Isaac Newton, who showed that Apollonius' problem is equivalent to finding a position from the differences of its distances to three known points. This has applications in navigation and positioning systems such as LORAN.

Later mathematicians introduced algebraic methods, which transform a geometric problem into algebraic equations. These methods were simplified by exploiting symmetries inherent in the problem of Apollonius: for instance solution circles generically occur in pairs, with one solution enclosing the given circles that the other excludes (Figure 2). Joseph Diaz Gergonne used this symmetry to provide an elegant straightedge and compass solution, while other mathematicians used geometrical transformations such as reflection in a circle to simplify the configuration of the given circles. These developments provide a geometrical setting for algebraic methods (using Lie sphere geometry) and a classification of solutions according to 33 essentially different configurations of the given circles.

Apollonius' problem has stimulated much further work. Generalizations to three dimensions—constructing a sphere tangent to four given spheres—and beyond have been studied. The configuration of three mutually tangent circles has received particular attention. René Descartes gave a formula relating the radii of the solution circles and the given circles, now known as Descartes' theorem. Solving Apollonius' problem iteratively in this case leads to the Apollonian gasket, which is one of the earliest fractals to be described in print, and is important in number theory via Ford circles and the Hardy–Littlewood circle method.

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