quality category - перевод на немецкий
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quality category - перевод на немецкий

Dg category; Dg-category; DG category; DG-category

quality category      
Qualitätskategorie, Qualitätsstufe (Einstufungsgrad der israelischen Armee nach Tauglichkeit und Eignungsfähigkeit)
quality circles         
GROUP OF WORKERS WHO MEET REGULARLY TO IDENTIFY, ANALYZE AND SOLVE WORK-RELATED PROBLEMS
Quality circles; Quality Circles; Quality control circle; Management quality circle
Arbeitskreise (System der Leitung in dem Arbeitsteams Lösungen finden)
quality assurance         
WAY OF PREVENTING MISTAKES OR DEFECTS IN MANUFACTURED PRODUCTS AND AVOIDING PROBLEMS WHEN DELIVERING SOLUTIONS OR SERVICES TO CUSTOMERS; (ISO 9000) PART OF QUALITY MANAGEMENT FOCUSED ON PROVIDING CONFIDENCE THAT QUALITY REQUIREMENTS WILL BE FULFILLED
Quality assessment; Quality Assessment; Quality Assurance; Systems assurance; Quality assurance program; Aseguradores de la calidad; QA Engineer
Sicherung der Qualität, Qualitätssicherung

Определение

quality circle
A quality circle is a small group of workers and managers who meet to solve problems and improve the quality of the organization's products or services. (BUSINESS)
Riddick's first move was to form a quality circle.
N-COUNT

Википедия

Differential graded category

In mathematics, especially homological algebra, a differential graded category, often shortened to dg-category or DG category, is a category whose morphism sets are endowed with the additional structure of a differential graded Z {\displaystyle \mathbb {Z} } -module.

In detail, this means that Hom ( A , B ) {\displaystyle \operatorname {Hom} (A,B)} , the morphisms from any object A to another object B of the category is a direct sum

n Z Hom n ( A , B ) {\displaystyle \bigoplus _{n\in \mathbb {Z} }\operatorname {Hom} _{n}(A,B)}

and there is a differential d on this graded group, i.e., for each n there is a linear map

d : Hom n ( A , B ) Hom n + 1 ( A , B ) {\displaystyle d\colon \operatorname {Hom} _{n}(A,B)\rightarrow \operatorname {Hom} _{n+1}(A,B)} ,

which has to satisfy d d = 0 {\displaystyle d\circ d=0} . This is equivalent to saying that Hom ( A , B ) {\displaystyle \operatorname {Hom} (A,B)} is a cochain complex. Furthermore, the composition of morphisms Hom ( A , B ) Hom ( B , C ) Hom ( A , C ) {\displaystyle \operatorname {Hom} (A,B)\otimes \operatorname {Hom} (B,C)\rightarrow \operatorname {Hom} (A,C)} is required to be a map of complexes, and for all objects A of the category, one requires d ( id A ) = 0 {\displaystyle d(\operatorname {id} _{A})=0} .